JEE Main 2026 · Session 2 · Shift 1 · Chemistry
Question 56
The solubility product constants of Ag₂CrO₄ and AgBr are 32x and 4y respectively at 298 K. The value of (molarity of Ag₂CrO₄ / molarity of AgBr) can be expressed as:
- A. 2·x^(1/3)/y
- B. 2sqrt(x/y)
- C. sqrt(x/y)
- D. x^(1/3)/sqrt(y)Correct answer
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Official source
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Question paper, page 22.