JEE Main 2026 · Session 2 · Shift 1 · Chemistry
Question 57
An electrochemical cell is constructed using half cells in the direction of spontaneous change Fe(OH)₂(s) + 2e⁻ → Fe(s) + 2OH⁻(aq) E° = −0.88 V and AgBr(s) + e⁻ → Ag(s) + Br⁻(aq) E° = +0.07 V Which of the following option is correct?
- A. Overall reaction Fe(s) + 2OH⁻(aq) + 2AgBr(s) ⇌ Fe(OH)₂(s) + 2Ag(s) + 2Br⁻(aq)Correct answer
- B. E°cell = −0.95 V
- C. Fe is reduced in the electrochemical cell
- D. E°cell is an extensive property
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Official source
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Question paper, page 22-23.